2cos^2 theta - 2sin^2 theta = 1,then theta = | vedclass

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(B) Given equation: $2\cos^2 	heta - 2\sin^2 	heta = 1$Take $2$ as a common factor: $2(\cos^2 	heta - \sin^2 	heta) = 1$Using the trigonometric id

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$30$

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(B) Given equation: $2\cos^2 	heta - 2\sin^2 	heta = 1$Take $2$ as a common factor: $2(\cos^2 	heta - \sin^2 	heta) = 1$Using the trigonometric identity $\cos 2	heta = \cos^2 	heta - \sin^2 	heta$,we get:$2\cos 2	heta = 1$$\cos 2	heta = \frac{1}{2}$Since $\cos 60^\circ = \frac{1}{2}$,we have:$2	heta = 60^\circ$$	heta = 30^\circ$

$2\cos^2 \theta - 2\sin^2 \theta = 1$,then $\theta = \dots \dots ^\circ$

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