$CH_3-C \equiv C-CH_3 \xrightarrow{(i) X, (ii) H_2O/Zn} CH_3-CO-CO-CH_3$. $X$ in the above reaction is:
- A$HNO_3$
- B$O_2$
- C$O_3$
- D$KMnO_4$
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