12 frac{5}{7} + 23 frac{3}{5} - 14 frac{1}{3} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the missing value be $x$.$12 \frac{5}{7} + 23 \frac{3}{5} - 14 \frac{1}{3} = 28 \frac{4}{7} - x$$x = 28 \frac{4}{7} + 14 \frac{1}{3} - 23 \fra

Vedclass · Accepted Answer

$6 \frac{62}{105}$

Vedclass · Answer

(C) Let the missing value be $x$.$12 \frac{5}{7} + 23 \frac{3}{5} - 14 \frac{1}{3} = 28 \frac{4}{7} - x$$x = 28 \frac{4}{7} + 14 \frac{1}{3} - 23 \frac{3}{5} - 12 \frac{5}{7}$Group the whole numbers and fractions:$x = (28 + 14 - 23 - 12) + (\frac{4}{7} + \frac{1}{3} - \frac{3}{5} - \frac{5}{7})$$x = 7 + (\frac{4}{7} - \frac{5}{7} + \frac{1}{3} - \frac{3}{5})$$x = 7 + (-\frac{1}{7} + \frac{5 - 9}{15})$$x = 7 - \frac{1}{7} - \frac{4}{15}$Find a common denominator for the fractions $(105)$:$x = 7 - (\frac{15 + 28}{105})$$x = 7 - \frac{43}{105}$$x = 6 + (1 - \frac{43}{105}) = 6 + \frac{62}{105} = 6 \frac{62}{105}$

$12 \frac{5}{7} + 23 \frac{3}{5} - 14 \frac{1}{3} = 28 \frac{4}{7} - ?$

Similar Questions

Which of the following statement$(s)$ is/are $TRUE$?
$I.$ $\sqrt{144} \times \sqrt{36} \times \sqrt[3]{125} \times \sqrt{121} = 3960$
$II.$ $\sqrt{324} + \sqrt{49} < \sqrt[3]{216} \times \sqrt{9}$

If $5 \sqrt{5} \times 5^{3} \div 5^{-\frac{3}{2}} = 5^{a+2},$ then the value of $a$ is

$\left[\frac{8(3.75)^{3}+1}{(7.5)^{2}-6.5}\right]$ is equal to

$34.95 + 240.016 + 23.98 = ?$

$(1.06+0.04)^{2}-?=4 \times 1.06 \times 0.04$

Vedclass Test Series

Exam Paper Generator

Online Exam Module