1 frac{7}{9} + 3 frac{5}{8} - 2 frac{1}{18} + | vedclass

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Question

(A) Let the missing value be $x$.$1 \frac{7}{9} + 3 \frac{5}{8} - 2 \frac{1}{18} + 4 \frac{7}{16} - 9 \frac{5}{18} + x = 0$Separate the whole numbers

Vedclass · Accepted Answer

$1 \frac{71}{144}$

Vedclass · Answer

(A) Let the missing value be $x$.$1 \frac{7}{9} + 3 \frac{5}{8} - 2 \frac{1}{18} + 4 \frac{7}{16} - 9 \frac{5}{18} + x = 0$Separate the whole numbers and fractions:$(1 + 3 - 2 + 4 - 9) + (\frac{7}{9} + \frac{5}{8} - \frac{1}{18} + \frac{7}{16} - \frac{5}{18}) + x = 0$$-3 + (\frac{7}{9} - \frac{6}{18}) + \frac{5}{8} + \frac{7}{16} + x = 0$$-3 + (\frac{14 - 6}{18}) + \frac{10 + 7}{16} + x = 0$$-3 + \frac{8}{18} + \frac{17}{16} + x = 0$$-3 + \frac{4}{9} + \frac{17}{16} + x = 0$$-3 + \frac{64 + 153}{144} + x = 0$$-3 + \frac{217}{144} + x = 0$$-3 + 1 \frac{73}{144} + x = 0$$-1 \frac{71}{144} + x = 0$$x = 1 \frac{71}{144}$

$1 \frac{7}{9} + 3 \frac{5}{8} - 2 \frac{1}{18} + 4 \frac{7}{16} - 9 \frac{5}{18} + ? = 0$

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