CsBr crystal has bcc structure. It has an edg | vedclass

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(B) In a $bcc$ structure,the ions are in contact along the body diagonal.The body diagonal of a cube with edge length $a$ is $\sqrt{3} a$.The shortest

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$3.72$

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(B) In a $bcc$ structure,the ions are in contact along the body diagonal.The body diagonal of a cube with edge length $a$ is $\sqrt{3} a$.The shortest interionic distance $(d)$ between the center ion and the corner ion is half of the body diagonal.$d = \frac{\sqrt{3}}{2} a$Given $a = 4.3 \ \mathring{A}$,$d = \frac{1.732}{2} 	imes 4.3 = 0.866 	imes 4.3 = 3.7238 \ \mathring{A} \approx 3.72 \ \mathring{A}$.

$CsBr$ crystal has $bcc$ structure. It has an edge length of $4.3 \ \mathring{A}$. The shortest interionic distance between $Cs^{+}$ and $Br^{-}$ ions is ................ $\mathring{A}$.

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