If gene A is dominant for height (tall) and g | vedclass

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(A) To determine the phenotype of the offspring,we analyze the cross $AABb 	imes aabb$ using a Punnett square or by considering individual gene segre

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(A) To determine the phenotype of the offspring,we analyze the cross $AABb 	imes aabb$ using a Punnett square or by considering individual gene segregation.$1$. For gene $A$: The cross is $AA 	imes aa$. All offspring will be $Aa$. Since $A$ is dominant for tall height,all offspring will be tall.$2$. For gene $B$: The cross is $Bb 	imes bb$. The offspring will be $50\% Bb$ (white) and $50\% bb$ (non-white/colored).$3$. The question asks for 'short and white' offspring.- Short height requires the genotype $aa$. Since all offspring are $Aa$,the probability of being short is $0$.- Therefore,the probability of being 'short and white' is $0 	imes 0.5 = 0$.

If gene $A$ is dominant for height (tall) and gene $B$ is dominant for white color,what proportion of the $F_1$ progeny from the cross $AABb \times aabb$ will be short and white (in $\%$)?

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