Genes p, q, and r are arranged on a chromosom | vedclass

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(D) The recombination frequency between two genes is directly proportional to the distance between them on the chromosome.Given:Recombination frequenc

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$q-p-r$

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(D) The recombination frequency between two genes is directly proportional to the distance between them on the chromosome.Given:Recombination frequency between $p$ and $q = 10 \% \implies$ distance $= 10 	ext{ map units}$.Recombination frequency between $q$ and $r = 20 \% \implies$ distance $= 20 	ext{ map units}$.Recombination frequency between $p$ and $r = 10 \% \implies$ distance $= 10 	ext{ map units}$.Since the distance between $q$ and $r$ $(20 	ext{ units})$ is the sum of the distances between $p$ and $q$ $(10 	ext{ units})$ and $p$ and $r$ $(10 	ext{ units})$,it implies that gene $p$ lies between $q$ and $r$.Therefore,the order of the genes on the chromosome is $q-p-r$ or $r-p-q$.

Genes $p, q,$ and $r$ are arranged on a chromosome. If the recombination frequency between $p$ and $q$ is $10 \%$,the recombination frequency between $q$ and $r$ is $20 \%$,and the recombination frequency between $p$ and $r$ is $10 \%$,what is the order of the genes on the chromosome?

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