What is the pitch of one turn of the DNA heli | vedclass

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Question

(A) In the $B-DNA$ structure,the distance between two consecutive base pairs is $0.34 \, nm$ $(3.4 \, \mathring{A})$.One full turn of the $DNA$ helix

Vedclass · Accepted Answer

$3.4 \, nm$

Vedclass · Answer

(A) In the $B-DNA$ structure,the distance between two consecutive base pairs is $0.34 \, nm$ $(3.4 \, \mathring{A})$.One full turn of the $DNA$ helix contains $10$ base pairs.Therefore,the pitch of one turn is calculated as $10 	imes 0.34 \, nm = 3.4 \, nm$ (or $34 \, \mathring{A}$).Since $3.4 \, nm$ is equivalent to $34 \, \mathring{A}$,and the options provided list $3.4 \, nm$ as the correct value for the pitch,option $A$ is the correct answer.

What is the pitch of one turn of the $DNA$ helix?

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