Does the sequence $-2, 2, -2, 2, -2, \ldots$ form an $AP$? If it forms an $AP$,write the next two terms.

(N/A) To check if the sequence forms an $AP$,we calculate the common difference $d$ between consecutive terms.
First,calculate the difference between the second and first term:
$a_{2} - a_{1} = 2 - (-2) = 2 + 2 = 4$
Next,calculate the difference between the third and second term:
$a_{3} - a_{2} = -2 - 2 = -4$
Since $a_{2} - a_{1} \neq a_{3} - a_{2}$ (i.e.,$4 \neq -4$),the common difference is not constant.
Therefore,the given list of numbers does not form an $AP$.