The ^{18}O isotope of oxygen will have: | vedclass

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(D) The isotope of oxygen is represented as $^{18}_{8}O$.In this notation,the subscript $8$ represents the atomic number $(Z)$,which is the number of

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$10$ neutrons and $8$ protons

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(D) The isotope of oxygen is represented as $^{18}_{8}O$.In this notation,the subscript $8$ represents the atomic number $(Z)$,which is the number of protons.The superscript $18$ represents the mass number $(A)$,which is the sum of protons and neutrons $(A = Z + N)$.Therefore,the number of neutrons $(N)$ is calculated as $N = A - Z = 18 - 8 = 10$.Thus,the isotope has $8$ protons and $10$ neutrons.

The $^{18}O$ isotope of oxygen will have:

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