Let $A(4, 2), B(6, 5)$ and $C(1, 4)$ be the vertices of $\Delta ABC$. Find the coordinates of the centroid of the triangle.

(N/A) The coordinates of the centroid of a triangle with vertices $(x_1, y_1), (x_2, y_2),$ and $(x_3, y_3)$ are given by the formula:
Centroid $= \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)$
Given vertices are $A(4, 2), B(6, 5),$ and $C(1, 4)$.
Here,$x_1 = 4, y_1 = 2, x_2 = 6, y_2 = 5, x_3 = 1, y_3 = 4$.
Substituting these values into the formula:
Centroid $= \left( \frac{4 + 6 + 1}{3}, \frac{2 + 5 + 4}{3} \right)$
$= \left( \frac{11}{3}, \frac{11}{3} \right)$
Thus,the coordinates of the centroid are $\left( \frac{11}{3}, \frac{11}{3} \right)$.