(sec A + tan A)(1 - sin A) = dots | vedclass

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Question

(C) Given expression: $(\sec A + 	an A)(1 - \sin A)$Step $1$: Convert $\sec A$ and $	an A$ into terms of $\sin A$ and $\cos A$:$(\frac{1}{\cos A} +

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$\cos A$

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(C) Given expression: $(\sec A + 	an A)(1 - \sin A)$Step $1$: Convert $\sec A$ and $	an A$ into terms of $\sin A$ and $\cos A$:$(\frac{1}{\cos A} + \frac{\sin A}{\cos A})(1 - \sin A)$Step $2$: Combine the fractions:$(\frac{1 + \sin A}{\cos A})(1 - \sin A)$Step $3$: Multiply the numerators:$\frac{(1 + \sin A)(1 - \sin A)}{\cos A}$Step $4$: Use the identity $(a + b)(a - b) = a^2 - b^2$:$\frac{1 - \sin^2 A}{\cos A}$Step $5$: Use the identity $1 - \sin^2 A = \cos^2 A$:$\frac{\cos^2 A}{\cos A} = \cos A$

$(\sec A + \tan A)(1 - \sin A) = \dots$

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