In triangle ABC,BC = AB and angle B = 80^{cir | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In $	riangle ABC$,we are given that $BC = AB$.Since the sides opposite to equal angles are equal,the angles opposite to equal sides are also equa

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(A) In $	riangle ABC$,we are given that $BC = AB$.Since the sides opposite to equal angles are equal,the angles opposite to equal sides are also equal.Therefore,$\angle A = \angle C$.We know that the sum of all interior angles of a triangle is $180^{\circ}$.So,$\angle A + \angle B + \angle C = 180^{\circ}$.Substituting the given values: $\angle A + 80^{\circ} + \angle A = 180^{\circ}$.$2 \angle A + 80^{\circ} = 180^{\circ}$.$2 \angle A = 180^{\circ} - 80^{\circ}$.$2 \angle A = 100^{\circ}$.$\angle A = 100^{\circ} / 2 = 50^{\circ}$.

In $\triangle ABC$,$BC = AB$ and $\angle B = 80^{\circ}$. Then $\angle A$ is equal to: (in $^{\circ}$)

Similar Questions

"If two angles and a side of one triangle are equal to two angles and a side of another triangle,then the two triangles must be congruent." Is the statement true? Why?

In $\Delta ABC$,$AB = AC$ and $\angle B = 75^{\circ}$,then $\angle C = \dots$ (in $^{\circ}$)

There can be $\ldots \ldots \ldots$ one-one correspondences between two triangles.

The difference of any two sides of a triangle is $\ldots \ldots \ldots$ than the third side.

In $\Delta ABC$,$AB = AC$ and $AD$ is an altitude to the base $BC$. Prove that $D$ is the midpoint of $BC$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module