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(B) Total number of bulbs $= 80$.Let $E$ be the event that the bulb selected at random from the lot has a lifetime of $1150 	ext{ hours}$.From the fr

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(B) Total number of bulbs $= 80$.Let $E$ be the event that the bulb selected at random from the lot has a lifetime of $1150 	ext{ hours}$.From the frequency table provided,we observe that the lifetimes recorded are $300, 500, 700, 900,$ and $1100 	ext{ hours}$.Since there is no entry for $1150 	ext{ hours}$,the number of favorable outcomes for event $E$ is $0$.Therefore,the probability $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{0}{80} = 0$.

Lifetime (in hours)	$300$	$500$	$700$	$900$	$1100$
Frequency	$10$	$12$	$23$	$25$	$10$

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