If $\tan \theta = \sqrt{3}$,then $\theta = \ldots$ (in $^\circ$)
- A$30$
- B$45$
- C$60$
- D$90$
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Similar Questions
Evaluate the following:
$\frac{5 \cos ^{2} 60^{\circ}+4 \sec ^{2} 30^{\circ}-\tan ^{2} 45^{\circ}}{\sin ^{2} 30^{\circ}+\cos ^{2} 30^{\circ}}$ (in $/12$)
$\frac{5 \cos ^{2} 60^{\circ}+4 \sec ^{2} 30^{\circ}-\tan ^{2} 45^{\circ}}{\sin ^{2} 30^{\circ}+\cos ^{2} 30^{\circ}}$ (in $/12$)
Medium
View Solution$\frac{2 \tan 30^{\circ}}{1+\tan ^{2} 30^{\circ}} = ?$
Medium
View Solution$\sin 60^{\circ} \sin 45^{\circ} + \cos 60^{\circ} \cos 45^{\circ} = \ldots \ldots \ldots \ldots$
Easy
View Solution$\frac{1-\tan ^{2} 45^{\circ}}{1+\tan ^{2} 45^{\circ}}=$
Easy
View Solution$\frac{\sin 60^{\circ} + \cos 30^{\circ}}{1 + \sin 30^{\circ} + \cos 60^{\circ}} = \dots$
Easy
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