overline{AB} is a diameter of a circle having | vedclass

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(B) Since $\overline{AB}$ is the diameter of the circle,the centre $P$ is the midpoint of the diameter $\overline{AB}$.Using the midpoint formula,the

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$(4, -4)$

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(B) Since $\overline{AB}$ is the diameter of the circle,the centre $P$ is the midpoint of the diameter $\overline{AB}$.Using the midpoint formula,the coordinates of $P$ are given by $\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$.Substituting the values $A(5, -6)$ and $B(3, -2)$:$P = \left( \frac{5 + 3}{2}, \frac{-6 + (-2)}{2} \right)$$P = \left( \frac{8}{2}, \frac{-8}{2} \right)$$P = (4, -4)$.

$\overline{AB}$ is a diameter of a circle having the centre $P$. If $A(5, -6)$ and $B(3, -2)$,then the coordinates of $P = \dots$

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