85 times 75 = ldots ldots ldots | vedclass

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Question

(B) To calculate $85 	imes 75$,we can use the algebraic identity $(a - b)(a + b) = a^2 - b^2$.We can write $85$ as $(80 + 5)$ and $75$ as $(80 - 5)$.

Vedclass · Accepted Answer

$6375$

Vedclass · Answer

(B) To calculate $85 	imes 75$,we can use the algebraic identity $(a - b)(a + b) = a^2 - b^2$.We can write $85$ as $(80 + 5)$ and $75$ as $(80 - 5)$.Thus,$85 	imes 75 = (80 + 5)(80 - 5)$.Using the identity $a^2 - b^2$,where $a = 80$ and $b = 5$:$= 80^2 - 5^2$$= 6400 - 25$$= 6375$.

$85 \times 75 = \ldots \ldots \ldots$

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