x=2 is a solution of the equation ldots ldots | vedclass

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Question

(A) To determine which equation has $x=2$ as a solution,we substitute $x=2$ into each given equation and check if the result is $0$.For option $A$: $x

Vedclass · Accepted Answer

$x^{2}-3x+2=0$

Vedclass · Answer

(A) To determine which equation has $x=2$ as a solution,we substitute $x=2$ into each given equation and check if the result is $0$.For option $A$: $x^{2}-3x+2=0$Substitute $x=2$: $(2)^{2}-3(2)+2 = 4-6+2 = 0$.Since the result is $0$,$x=2$ is a solution for this equation.For option $B$: $x^{2}+x+2=0$Substitute $x=2$: $(2)^{2}+2+2 = 4+2+2 = 8 
eq 0$.For option $C$: $x^{2}-2x+2=0$Substitute $x=2$: $(2)^{2}-2(2)+2 = 4-4+2 = 2 
eq 0$.For option $D$: $2x^{2}+2x+1=0$Substitute $x=2$: $2(2)^{2}+2(2)+1 = 2(4)+4+1 = 8+4+1 = 13 
eq 0$.Therefore,the correct option is $A$.

$x=2$ is a solution of the equation $\ldots \ldots \ldots \ldots.$

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