Which of the following sequences is not an A. | vedclass

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(D) An Arithmetic Progression $(A.P.)$ is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant i

Vedclass · Accepted Answer

$\frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \ldots$

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(D) An Arithmetic Progression $(A.P.)$ is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant is called the common difference $(d)$.For option $A$: $-3 - (-1) = -2$,$-5 - (-3) = -2$,$-7 - (-5) = -2$. Since the difference is constant,it is an $A.P.$For option $B$: $15 - 20 = -5$,$10 - 15 = -5$,$5 - 10 = -5$. Since the difference is constant,it is an $A.P.$For option $C$: $-2 - 2 = -4$,$-6 - (-2) = -4$,$-10 - (-6) = -4$. Since the difference is constant,it is an $A.P.$For option $D$: $\frac{1}{3} - \frac{1}{2} = \frac{2-3}{6} = -\frac{1}{6}$,while $\frac{1}{4} - \frac{1}{3} = \frac{3-4}{12} = -\frac{1}{12}$. Since the differences are not equal,this sequence is not an $A.P.$

Which of the following sequences is not an $A.P.$?

Similar Questions

Write the first four terms of the $AP,$ when the first term $a$ and the common difference $d$ are given as follows: $a = -1, d = \frac{1}{2}$

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