In Delta ABC,angle B is a right angle. If AB | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In $\Delta ABC$,$m\angle B = 90^{\circ}$,$AB = 24$,and $BC = 7$.Using the Pythagoras theorem:$AC^2 = AB^2 + BC^2$$AC^2 = (24)^2 + (7)^2$$AC^2 = 57

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) In $\Delta ABC$,$m\angle B = 90^{\circ}$,$AB = 24$,and $BC = 7$.Using the Pythagoras theorem:$AC^2 = AB^2 + BC^2$$AC^2 = (24)^2 + (7)^2$$AC^2 = 576 + 49$$AC^2 = 625$$AC = \sqrt{625} = 25$.The radius $r$ of the incircle of a right-angled triangle is given by the formula:$r = \frac{AB + BC - AC}{2}$$r = \frac{24 + 7 - 25}{2}$$r = \frac{31 - 25}{2}$$r = \frac{6}{2} = 3$.Therefore,the radius of the circle is $3$.

In $\Delta ABC$,$\angle B$ is a right angle. If $AB = 24$ and $BC = 7$,then the radius of the circle touching all three sides of $\Delta ABC$ is $\ldots \ldots \ldots \ldots$.

Similar Questions

In $Fig.$,$AB$ and $CD$ are common tangents to two circles of unequal radii. Prove that $AB = CD$.

If a hexagon $ABCDEF$ circumscribes a circle,prove that $AB + CD + EF = BC + DE + FA$.

In the following figure,find $m \angle PBA$.

If $\odot(O, 5)$ touches all the sides of a square,then the perimeter of the square is .... .

Prove that the tangent drawn at the mid-point of an arc of a circle is parallel to the chord joining the end points of the arc.

Vedclass Test Series

Exam Paper Generator

Online Exam Module