(i) F_3CCOOH(ii) CH_3COOH(iii) C_6H_5COOH( | vedclass

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(C) The acidic strength of carboxylic acids depends on the electron-withdrawing or electron-donating groups attached to the carboxyl group.$1$. $F_3CC

Vedclass · Accepted Answer

$iv > ii > iii > i$

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(C) The acidic strength of carboxylic acids depends on the electron-withdrawing or electron-donating groups attached to the carboxyl group.$1$. $F_3CCOOH$: The strong electron-withdrawing effect of three fluorine atoms significantly increases acidity.$2$. $C_6H_5COOH$: The phenyl group exerts an electron-withdrawing effect through resonance and induction,making it more acidic than aliphatic acids.$3$. $CH_3COOH$: The methyl group is electron-donating (+$I$ effect),which decreases acidity compared to benzoic acid.$4$. $CH_3CH_2COOH$: The ethyl group is a stronger electron-donating group (+$I$ effect) than the methyl group,further decreasing acidity.Thus,the order of acidic strength is: $i > iii > ii > iv$.Since $pK_a$ is inversely proportional to acidic strength $(pK_a = -\log K_a)$,the order of $pK_a$ values is the reverse of the acidic strength order: $iv > ii > iii > i$.

$(i) \ F_3CCOOH$
$(ii) \ CH_3COOH$
$(iii) \ C_6H_5COOH$
$(iv) \ CH_3CH_2COOH$
Correct order of $pK_a$ value is:

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$(i) \ F_3CCOOH$$(ii) \ CH_3COOH$$(iii) \ C_6H_5COOH$$(iv) \ CH_3CH_2COOH$Correct order of $pK_a$ value is: