$(a)$ $A$ sample of vitamin $C$ is known to contain $2.58 \times 10^{24}$ oxygen atoms. How many moles of oxygen atoms are present in the sample?
$(b)$ Write one word for the following:
$(i)$ In a balanced chemical equation,the sum of the masses of reactants and products remains unchanged.
$(ii)$ $A$ group of atoms carrying a fixed charge on them.
$(c)$ Write chemical formulae of the following compounds:
$(i)$ Sodium phosphate
$(ii)$ Ammonium carbonate
$(b)$ Write one word for the following:
$(i)$ In a balanced chemical equation,the sum of the masses of reactants and products remains unchanged.
$(ii)$ $A$ group of atoms carrying a fixed charge on them.
$(c)$ Write chemical formulae of the following compounds:
$(i)$ Sodium phosphate
$(ii)$ Ammonium carbonate
(N/A) Since $6.022 \times 10^{23}$ oxygen atoms are present in $1$ mole of oxygen atoms,the number of moles in $2.58 \times 10^{24}$ oxygen atoms is calculated as:
$\text{Moles} = \frac{2.58 \times 10^{24}}{6.022 \times 10^{23}} \approx 4.284 \text{ moles}$.
$(b)$ $(i)$ Law of conservation of mass.
$(ii)$ Polyatomic ion.
$(c)$ $(i)$ The formula for Sodium phosphate is $Na_{3}PO_{4}$.
$(ii)$ The formula for Ammonium carbonate is $(NH_{4})_{2}CO_{3}$.
$\text{Moles} = \frac{2.58 \times 10^{24}}{6.022 \times 10^{23}} \approx 4.284 \text{ moles}$.
$(b)$ $(i)$ Law of conservation of mass.
$(ii)$ Polyatomic ion.
$(c)$ $(i)$ The formula for Sodium phosphate is $Na_{3}PO_{4}$.
$(ii)$ The formula for Ammonium carbonate is $(NH_{4})_{2}CO_{3}$.
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