A uniform rod of mass M and length L is place | vedclass

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(A) According to Newton's second law for the motion of the centre of mass,the net external force acting on a system is equal to the product of the tot

Vedclass · Accepted Answer

$F/M$

Vedclass · Answer

(A) According to Newton's second law for the motion of the centre of mass,the net external force acting on a system is equal to the product of the total mass of the system and the acceleration of its centre of mass.Mathematically,$F_{ext} = M_{total} \cdot a_{cm}$.Here,the total mass of the rod is $M$ and the external force applied is $F$.Therefore,$F = M \cdot a_{cm}$.Solving for the acceleration of the centre of mass,we get $a_{cm} = F/M$.

$A$ uniform rod of mass $M$ and length $L$ is placed on a smooth horizontal surface. $A$ horizontal force $F$ is applied at one end of the rod perpendicular to its length. The acceleration of the centre of mass of the rod is:

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