When KI and CuSO_4 solutions are mixed,the pr | vedclass

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Question

(C) When $KI$ is added to $CuSO_4$,the initial reaction is: $2KI + CuSO_4 	o CuI_2 + K_2SO_4$ $CuI_2$ is unstable and immediately undergoes reduction

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$K_2SO_4 + Cu_2I_2 + I_2$

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(C) When $KI$ is added to $CuSO_4$,the initial reaction is: $2KI + CuSO_4 	o CuI_2 + K_2SO_4$ $CuI_2$ is unstable and immediately undergoes reduction to form $Cu_2I_2$ and $I_2$: $2CuI_2 	o Cu_2I_2 + I_2$ Combining these,the overall reaction is: $2CuSO_4 + 4KI 	o Cu_2I_2 + 2K_2SO_4 + I_2$ Thus,the final mixture contains $K_2SO_4$,$Cu_2I_2$,and $I_2$.

When $KI$ and $CuSO_4$ solutions are mixed,the products formed are:

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