AB_2 is 10% dissociated in water to A^{2+} an | vedclass

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(D) For the dissociation reaction: $AB_2 \rightleftharpoons A^{2+} + 2B^-$,the number of ions produced per formula unit is $n = 3$.Given the degree of

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$106$

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(D) For the dissociation reaction: $AB_2 ightleftharpoons A^{2+} + 2B^-$,the number of ions produced per formula unit is $n = 3$.Given the degree of dissociation $\alpha = 10\% = 0.1$.The van't Hoff factor $i$ is calculated as $i = 1 + (n-1)\alpha = 1 + (3-1)0.1 = 1 + 0.2 = 1.2$.The elevation in boiling point is given by $\Delta T_b = i \cdot K_b \cdot m$.Substituting the values: $\Delta T_b = 1.2 	imes 0.5 	ext{ K kg mol}^{-1} 	imes 10.0 	ext{ mol kg}^{-1} = 6 	ext{ K}$ (or $6^\circ C$).The boiling point of the solution is $T_b = T_b^\circ + \Delta T_b = 100^\circ C + 6^\circ C = 106^\circ C$.

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