Identify $A$ and $B$ in the following reaction sequence:
Aniline $\xrightarrow[KCN]{NaNO_2/HCl} (A)$ $\xrightarrow{SnCl_2/HCl/H_3O^+} (B)$

  • A
    $(A)$: Phenyl diazonium chloride,$(B)$: Benzaldehyde
  • B
    $(A)$: Phenyl diazonium chloride,$(B)$: Chlorobenzene
  • C
    $(A)$: Benzonitrile,$(B)$: Benzaldehyde
  • D
    $(A)$: Benzonitrile,$(B)$: Chlorobenzene

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Ethanoic acid on heating with ammonia forms compound $A$ which on treatment with bromine and sodium hydroxide gives compound $B$. Compound $B$ on treatment with $NaNO_2/dil. HCl$ gives compound $C$. The compounds $A, B$ and $C$ respectively are

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