1 molal aqueous solution of an electrolyte A_ | vedclass

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(C) The electrolyte $A_{2}B_{3}$ dissociates as: $A_{2}B_{3} \rightarrow 2A^{3+} + 3B^{2-}$.The number of ions produced per formula unit is $n = 2 + 3

Vedclass · Accepted Answer

$375$

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(C) The electrolyte $A_{2}B_{3}$ dissociates as: $A_{2}B_{3} ightarrow 2A^{3+} + 3B^{2-}$.The number of ions produced per formula unit is $n = 2 + 3 = 5$.The degree of dissociation $\alpha = 0.60$.The van't Hoff factor $i = 1 + \alpha(n - 1) = 1 + 0.60(5 - 1) = 1 + 0.60(4) = 1 + 2.4 = 3.4$.The elevation in boiling point is given by $\Delta T_{b} = i K_{b} m$.Substituting the values: $\Delta T_{b} = 3.4 	imes 0.52 	imes 1 = 1.768 \ K$.The boiling point of the solution $T_{b} = T_{b}^{\circ} + \Delta T_{b} = 373.15 + 1.768 = 374.918 \ K$.Rounding off to the nearest integer,we get $375 \ K$.

$1$ molal aqueous solution of an electrolyte $A_{2}B_{3}$ is $60\%$ ionised. The boiling point of the solution at $1 \ atm$ is ......... $K$.
(Rounded-off to the nearest integer)
[Given $K_{b}$ for $H_{2}O = 0.52 \ K \ kg \ mol^{-1}$]

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$1$ molal aqueous solution of an electrolyte $A_{2}B_{3}$ is $60\%$ ionised. The boiling point of the solution at $1 \ atm$ is ......... $K$.(Rounded-off to the nearest integer)[Given $K_{b}$ for $H_{2}O = 0.52 \ K \ kg \ mol^{-1}$]