$LiAlH_4$ converts acetic acid into

The compounds that produce $CO_2$ with aqueous $NaHCO_3$ solution are:
$A$. Benzoic acid
$B$. Phenol
$C$. $2,4,6$-Trinitrophenol (Picric acid)
$D$. Cyclohexanecarboxylic acid
$E$. $4$-Methoxyphenol
Choose the correct answer from the options given below:

Arrange the following compounds in increasing order of their acidic strength:
$(A)$ $CH_3COOH$
$(B)$ $Ph-CH_2-COOH$
$(C)$ $Br-CH_2-COOH$
$(D)$ $O_2N-CH_2-COOH$

The major product $(A)$ is:

What are $A$ and $B$ in the following reaction sequence?
$CH_3COOH$ $\xrightarrow{A} X$ $\xrightarrow[H^{+}]{Y} \underset{\text{(Analgesic drug)}}{B}$

$R-CO-OR' \xrightarrow{LiAlH_4} B + C$. Both $B$ and $C$ give a positive iodoform test. $R$ and $R'$ can be: