A xrightarrow{K_2Cr_2O_7 / text{dil. } H_2SO_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The final product is $tert$-butyl alcohol,which is a tertiary alcohol formed by the reaction of a ketone with a Grignard reagent.Step $1$: The rea

Vedclass · Accepted Answer

$CH_3-CH(OH)-CH_3$

Vedclass · Answer

(B) The final product is $tert$-butyl alcohol,which is a tertiary alcohol formed by the reaction of a ketone with a Grignard reagent.Step $1$: The reaction $B \xrightarrow{CH_3MgI / H_2O} CH_3-C(CH_3)(OH)-CH_3$ indicates that $B$ must be acetone $(CH_3-CO-CH_3)$.Step $2$: The reaction $A \xrightarrow{K_2Cr_2O_7 / 	ext{dil. } H_2SO_4} B$ shows that $A$ is an alcohol that oxidizes to acetone. Secondary alcohols oxidize to ketones.Therefore,$A$ is isopropyl alcohol $(CH_3-CH(OH)-CH_3)$.

$A$ $\xrightarrow{K_2Cr_2O_7 / \text{dil. } H_2SO_4} B$ $\xrightarrow{CH_3MgI / H_2O} CH_3-C(CH_3)(OH)-CH_3$. The reactant $A$ is:

Similar Questions

The correct order of the rate of acid-mediated dehydration reaction of the following compounds is:

Which of the following reactions is not feasible?

Tertiary alcohols $(3^{\circ})$ having at least four carbon atoms upon drastic oxidation yield carboxylic acid with:

In the reaction $CH_2OH-CHOH-CH_2OH + COOH-COOH \xrightarrow{110^\circ C} (A)$,product $(A)$ will be:

$HC \equiv CH$ $\xrightarrow[HgSO_4]{H_2SO_4} \,\,$ $\xrightarrow[HOH]{CH_3MgBr} \,\,$ $\xrightarrow{P/Br_2} (X)$; $(X)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module