(A) $1$. Parental generation $(P)$: $BB$ (Black) $\times$ $bb$ (Brown).$2$. $F_1$ generation: All offspring are $Bb$ (Heterozygous black).$3$. Interbr

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(A) $1$. Parental generation $(P)$: $BB$ (Black) $\times$ $bb$ (Brown).$2$. $F_1$ generation: All offspring are $Bb$ (Heterozygous black).$3$. Interbreeding $F_1$ generation: $Bb \times Bb$.$4$. $F_2$ generation genotypes: $1 BB : 2 Bb : 1 bb$.$5$. Phenotypic ratio: $3$ Black $(BB, Bb)$ : $1$ Brown $(bb)$.$6$. Therefore,the percentage of black-coated mice is $(3/4) \times 100 = 75\, \%$.

Class 12 Biology Principles of Inheritance and Variation Inheritance of one gene

Medium

$BB =$ alleles for black coat colour
$bb =$ alleles for brown coat colour
If the offspring of a cross between a black mouse $(BB)$ and a brown mouse $(bb)$ are allowed to interbreed,find the percentage of black-coated mice in the $F_2$ generation.

A
$75\, \%$
B
$50\, \%$
C
Cross is not possible because black and brown mice are different species
D
$100\, \%$

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Principles of Inheritance and Variation

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Inheritance of one gene

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$BB =$ alleles for black coat colour$bb =$ alleles for brown coat colourIf the offspring of a cross between a black mouse $(BB)$ and a brown mouse $(bb)$ are allowed to interbreed,find the percentage of black-coated mice in the $F_2$ generation.

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$BB =$ alleles for black coat colour
$bb =$ alleles for brown coat colour
If the offspring of a cross between a black mouse $(BB)$ and a brown mouse $(bb)$ are allowed to interbreed,find the percentage of black-coated mice in the $F_2$ generation.