Phenol xrightarrow[Distillation]{Zn} A xright | vedclass

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(D) $1$. Phenol reacts with $Zn$ dust upon distillation to form Benzene $(A = C_6H_6)$.$2$. Benzene undergoes nitration with a mixture of $Conc. H_2SO

Vedclass · Accepted Answer

$C_6H_6, C_6H_5NO_2$ and hydrazobenzene

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(D) $1$. Phenol reacts with $Zn$ dust upon distillation to form Benzene $(A = C_6H_6)$.$2$. Benzene undergoes nitration with a mixture of $Conc. H_2SO_4$ and $Conc. HNO_3$ to form Nitrobenzene $(B = C_6H_5NO_2)$.$3$. Nitrobenzene undergoes reduction in the presence of $Zn$ and $NaOH$ (alkaline medium) to form Hydrazobenzene $(C = C_6H_5-NH-NH-C_6H_5)$.Thus,the correct sequence is $C_6H_6, C_6H_5NO_2$ and hydrazobenzene.

$Phenol$ $\xrightarrow[Distillation]{Zn} A$ $\xrightarrow[Conc. H_2SO_4]{Conc. HNO_3} B$ $\xrightarrow[NaOH]{Zn} C$
In the above reaction,$A$,$B$,and $C$ are the following compounds:

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$Phenol$ $\xrightarrow[Distillation]{Zn} A$ $\xrightarrow[Conc. H_2SO_4]{Conc. HNO_3} B$ $\xrightarrow[NaOH]{Zn} C$In the above reaction,$A$,$B$,and $C$ are the following compounds: