In photosynthesis,if we radiolabel the oxygen | vedclass

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(B) In the process of photosynthesis,the chemical equation is $6CO_2 + 12H_2O \rightarrow C_6H_{12}O_6 + 6H_2O + 6O_2$.According to the experiments co

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$C_6H_{12}O_6$

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(B) In the process of photosynthesis,the chemical equation is $6CO_2 + 12H_2O \rightarrow C_6H_{12}O_6 + 6H_2O + 6O_2$.According to the experiments conducted by Van Niel and later confirmed by Ruben and Kamen using radioactive isotopes,the oxygen released as a byproduct $(O_2)$ comes from the water $(H_2O)$ molecule,not from $CO_2$.Conversely,the carbon and oxygen atoms from $CO_2$ are incorporated into the glucose $(C_6H_{12}O_6)$ molecule during the Calvin cycle (dark reaction).Therefore,if the oxygen in $CO_2$ is radiolabeled,the radiolabel will appear in the glucose $(C_6H_{12}O_6)$ produced.

In photosynthesis,if we radiolabel the oxygen atom in $CO_2$,which product will become radiolabeled?

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