If the length of DNA in an organism is 2.72 , | vedclass

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(B) The distance between two consecutive base pairs in $DNA$ is $0.34 \,nm$ or $0.34 	imes 10^{-6} \,mm$.Total length of $DNA = 2.72 \,mm$.Number of

Vedclass · Accepted Answer

$8 	imes 10^6$

Vedclass · Answer

(B) The distance between two consecutive base pairs in $DNA$ is $0.34 \,nm$ or $0.34 	imes 10^{-6} \,mm$.Total length of $DNA = 2.72 \,mm$.Number of base pairs = $\frac{	ext{Total length of DNA}}{	ext{Distance between two consecutive base pairs}}$.Number of base pairs = $\frac{2.72 \,mm}{0.34 	imes 10^{-6} \,mm}$.Number of base pairs = $\frac{2.72}{0.34} 	imes 10^6$.Number of base pairs = $8 	imes 10^6$ base pairs.

If the length of $DNA$ in an organism is $2.72 \,mm$,how many base pairs will be present in this organism?

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