When the pBR322 plasmid is cut with the Pst, | vedclass

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(C) The $pBR322$ plasmid contains two antibiotic resistance genes: $amp^R$ (ampicillin resistance) and $tet^R$ (tetracycline resistance).The $Pst\, I$

Vedclass · Accepted Answer

The $amp^R$ gene becomes inactive.

Vedclass · Answer

(C) The $pBR322$ plasmid contains two antibiotic resistance genes: $amp^R$ (ampicillin resistance) and $tet^R$ (tetracycline resistance).The $Pst\, I$ restriction site is located within the $amp^R$ gene sequence.When the plasmid is digested with $Pst\, I$,the $DNA$ is cut at the specific recognition site within the $amp^R$ gene.This insertion of foreign $DNA$ or disruption of the sequence leads to the insertional inactivation of the $amp^R$ gene,making the bacteria sensitive to ampicillin.

$(a)$ Restriction endonuclease	$(i)$ Joins the $DNA$ fragments
$(b)$ Restriction exonuclease	$(ii)$ Extends primers on genomic $DNA$ template
$(c)$ $DNA$ ligase	$(iii)$ Cuts $DNA$ at specific positions
$(d)$ $Taq$ polymerase	$(iv)$ Removes nucleotides from the ends of $DNA$

When the $pBR322$ plasmid is cut with the $Pst\, I$ restriction enzyme,which of the following occurs?

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