K is the force constant of a spring. The work | vedclass

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(D) The potential energy stored in a spring with force constant $K$ at an extension $x$ is given by $U = \frac{1}{2}Kx^2$.At extension $l_1$,the store

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$\frac{K}{2}(l_2^2 - l_1^2)$

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(D) The potential energy stored in a spring with force constant $K$ at an extension $x$ is given by $U = \frac{1}{2}Kx^2$.At extension $l_1$,the stored potential energy is $U_1 = \frac{1}{2}Kl_1^2$.At extension $l_2$,the stored potential energy is $U_2 = \frac{1}{2}Kl_2^2$.The work done $W$ in increasing the extension from $l_1$ to $l_2$ is equal to the change in potential energy:$W = U_2 - U_1$$W = \frac{1}{2}Kl_2^2 - \frac{1}{2}Kl_1^2$$W = \frac{1}{2}K(l_2^2 - l_1^2)$.

$K$ is the force constant of a spring. The work done in increasing its extension from $l_1$ to $l_2$ will be

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