0.5 g of an organic compound (X) with 60 % c | vedclass

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Question

(B) The percentage of carbon in an organic compound is given by the formula:$\% 	ext{Carbon} = \frac{12}{44} 	imes \frac{	ext{mass of } CO_2 	ext{

Vedclass · Accepted Answer

$11$

Vedclass · Answer

(B) The percentage of carbon in an organic compound is given by the formula:$\% 	ext{Carbon} = \frac{12}{44} 	imes \frac{	ext{mass of } CO_2 	ext{ formed}}{	ext{mass of compound taken}} 	imes 100$Given,$\% 	ext{Carbon} = 60$,$	ext{mass of compound} = 0.5 \ g$.Substituting the values:$60 = \frac{12}{44} 	imes \frac{	ext{mass of } CO_2}{0.5} 	imes 100$$	ext{mass of } CO_2 = \frac{60 	imes 44 	imes 0.5}{12 	imes 100} \ g$$	ext{mass of } CO_2 = \frac{1320}{1200} \ g = 1.1 \ g$Expressing $1.1 \ g$ in the form $........ 	imes 10^{-1} \ g$:$1.1 \ g = 11 	imes 10^{-1} \ g$Thus,the missing value is $11$.

$0.5 \ g$ of an organic compound $(X)$ with $60 \%$ carbon will produce $........ \times 10^{-1} \ g$ of $CO_2$ on complete combustion.

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