A_{(g)} rightleftharpoons 2B_{(g)} + C_{(g)}F | vedclass

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(C) The reaction is $A_{(g)} \rightleftharpoons 2B_{(g)} + C_{(g)}$.Let the initial pressure of $A$ be $P_0 = 450 \ mm \ Hg$.Let the pressure of $A$ t

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$3$

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(C) The reaction is $A_{(g)} ightleftharpoons 2B_{(g)} + C_{(g)}$.Let the initial pressure of $A$ be $P_0 = 450 \ mm \ Hg$.Let the pressure of $A$ that decomposes at time $t$ be $p$.At $t=0$: $P_A = 450, P_B = 0, P_C = 0$. Total pressure $P_i = 450 \ mm \ Hg$.At time $t$: $P_A = 450 - p, P_B = 2p, P_C = p$.Total pressure $P_t = (450 - p) + 2p + p = 450 + 2p$.Given $P_t = 720 \ mm \ Hg$,so $450 + 2p = 720$.$2p = 270 \implies p = 135 \ mm \ Hg$.The fraction of $A$ decomposed is $\alpha = \frac{p}{P_0} = \frac{135}{450} = 0.3$.Given $\alpha = x 	imes 10^{-1} = 0.3$,therefore $x = 3$.

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