Be(OH)_2 reacts with Sr(OH)_2 to yield an ion | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $Be(OH)_2$ is amphoteric in nature,while $Sr(OH)_2$ is basic in nature.These two undergo an acid-base neutralization reaction to form the salt $Sr

Vedclass · Accepted Answer

The element $Be$ is present in the cationic part of the ionic salt.

Vedclass · Answer

(D) $Be(OH)_2$ is amphoteric in nature,while $Sr(OH)_2$ is basic in nature.These two undergo an acid-base neutralization reaction to form the salt $Sr[Be(OH)_4]$.In this salt,$Sr^{2+}$ is the cation and $[Be(OH)_4]^{2-}$ is the complex anion.Therefore,$Be$ is present in the anionic part of the salt,not the cationic part.Thus,option $D$ is the incorrect statement.

$Be(OH)_2$ reacts with $Sr(OH)_2$ to yield an ionic salt. Choose the incorrect option related to this reaction from the following:

Similar Questions

Which compound is used in medicine as a barium meal for intestinal $X$-ray?

Which colour is developed in the solution when alkaline earth metals are dissolved in liquid ammonia?

Which of the following elements belongs to group $2$ and sixth period of the periodic table?

The correct order of thermal stability of hydroxides is

Which of the following produces hydrolith with dihydrogen?

Vedclass Test Series

Exam Paper Generator

Online Exam Module