$1 \ g$ of sodium hydroxide was treated with $25 \ mL$ of $0.75 \ M \ HCl$ solution. The mass of sodium hydroxide left unreacted is equal to:

One mole of $Cl_{2(g)}$ was passed into $2 \text{ L}$ of cold $2 \text{ M}$ $KOH$ solution. After the reaction, the concentrations of $Cl^{-}$, $ClO^{-}$ and $OH^{-}$ are respectively (assume volume remains constant):

In Ostwald's process for the manufacture of nitric acid,the first step involves the oxidation of ammonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum weight of nitric oxide that can be obtained starting only with $10.00 \ g$ of ammonia and $20.00 \ g$ of oxygen?

Sulphuric acid reacts with sodium hydroxide as follows:
$H_2SO_4 + 2NaOH \longrightarrow Na_2SO_4 + 2H_2O$
What will be the amount of sodium sulphate formed, when $1 \ L$ of $0.2 \ M$ sulphuric acid is allowed to react with $1 \ L$ of $0.2 \ M$ sodium hydroxide solution (in $g$)?

The amount of $BaSO_4$ formed upon mixing $100 \ mL$ of $20.8 \%$ $BaCl_2$ solution with $50 \ mL$ of $9.8 \%$ $H_2SO_4$ solution will be ............. $g$
( $Ba = 137, Cl = 35.5, S = 32, H = 1$ and $O = 16$ )

When $22.4 \ L$ of $H_{2(g)}$ is mixed with $5.6 \ L$ of $Cl_{2(g)}$,each at $S.T.P.$,the moles of $HCl_{(g)}$ formed after completion of the reaction is closest to $.... \ mol$.