B(OH)_3 + NaOH rightleftharpoons NaBO_2 + Na[ | vedclass

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(A) The reaction $B(OH)_3 + NaOH \rightleftharpoons Na[B(OH)_4]$ is an equilibrium reaction.By adding a $cis-1,2-diol$ (like glycerol or mannitol),a s

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addition of $cis-1,2-diol$

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(A) The reaction $B(OH)_3 + NaOH \rightleftharpoons Na[B(OH)_4]$ is an equilibrium reaction.By adding a $cis-1,2-diol$ (like glycerol or mannitol),a stable chelated complex is formed with the borate ion $[B(OH)_4]^-$.This removal of the product $[B(OH)_4]^-$ from the equilibrium mixture shifts the reaction in the forward direction according to Le Chatelier's principle.

$B(OH)_3 + NaOH \rightleftharpoons NaBO_2 + Na[B(OH)_4] + H_2O$
How can this reaction be made to proceed in the forward direction?

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$B(OH)_3 + NaOH \rightleftharpoons NaBO_2 + Na[B(OH)_4] + H_2O$How can this reaction be made to proceed in the forward direction?