STATEMENT-1: In a Meter Bridge experiment,a n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a Meter Bridge,the condition for the null point is given by $\frac{R_u}{R_s} = \frac{\ell}{100-\ell}$,where $R_u$ is the unknown resistance,$R_

Vedclass · Accepted Answer

$STATEMENT-1$ is False,$STATEMENT-2$ is True

Vedclass · Answer

(D) In a Meter Bridge,the condition for the null point is given by $\frac{R_u}{R_s} = \frac{\ell}{100-\ell}$,where $R_u$ is the unknown resistance,$R_s$ is the standard resistance,and $\ell$ is the balancing length.When the temperature of the unknown resistance $R_u$ increases,its resistance increases because $R_u(T) = R_0(1 + \alpha \Delta T)$.To keep the null point at the same position $\ell$,the ratio $\frac{R_u}{R_s}$ must remain constant.Since $R_u$ has increased,$R_s$ must also be increased to maintain the same ratio.$STATEMENT-1$ suggests decreasing $R_s$,which is incorrect.$STATEMENT-2$ is a well-known physical fact that the resistance of a metal increases with temperature.Therefore,$STATEMENT-1$ is False and $STATEMENT-2$ is True.

$S.No.$	$R$	$l$	$100-l$	$S = \left( \frac{100-l}{l} \right)R$
$1$	$20\,\Omega$	$43$	$57$	$26.51\,\Omega$
$2$	$30\,\Omega$	$51$	$49$	$28.82\,\Omega$
$3$	$40\,\Omega$	$59$	$41$	$27.80\,\Omega$
$4$	$60\,\Omega$	$70$	$30$	$25.71\,\Omega$

Similar Questions

The resistance in the left and right gaps of a meter bridge are $10 \Omega$ and $30 \Omega$ respectively. If the bridge is balanced,then the distance of the null point from the center of the wire is (in $cm$)

$A$ resistance of $20 \Omega$ is connected in the left gap of a metre bridge and an unknown resistance greater than $20 \Omega$ is connected in the right gap. When these resistances are interchanged,the balance point shifts by $20 \text{ cm}$. The unknown resistance is (in $\Omega$)

In a metre bridge experiment,the null point is obtained at $20 \,cm$ from the left end of the wire,when resistance $X$ is balanced against another resistance $Y$ $(X < Y)$. To balance a resistance $4X$ against $Y$,the new position of the null point from the same end will be: (in $\,cm$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module