STATEMENT-1: Pb^{4+} compounds are stronger o | vedclass

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Question

(C) $STATEMENT-1$ is True: Due to the inert pair effect,the stability of the $+4$ oxidation state decreases down the group $14$ $(C > Si > Ge > Sn > P

Vedclass · Accepted Answer

$STATEMENT-1$ is True,$STATEMENT-2$ is False

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(C) $STATEMENT-1$ is True: Due to the inert pair effect,the stability of the $+4$ oxidation state decreases down the group $14$ $(C > Si > Ge > Sn > Pb)$. Thus,$Pb^{4+}$ is highly unstable and acts as a strong oxidizing agent to reach the more stable $+2$ state.$STATEMENT-2$ is False: The inert pair effect states that the lower oxidation state $(+2)$ becomes more stable than the higher oxidation state $(+4)$ for the heavier members of group $14$ (like $Pb$). Therefore,the higher oxidation state is less stable for heavier members.

$STATEMENT-1$: $Pb^{4+}$ compounds are stronger oxidizing agents than $Sn^{4+}$ compounds.
$STATEMENT-2$: The higher oxidation states for the group $14$ elements are more stable for the heavier members of the group due to 'inert pair effect'.

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$STATEMENT-1$: $Pb^{4+}$ compounds are stronger oxidizing agents than $Sn^{4+}$ compounds.$STATEMENT-2$: The higher oxidation states for the group $14$ elements are more stable for the heavier members of the group due to 'inert pair effect'.