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(B) The power of the silvered lens system is given by $P = 2P_L + P_M$,where $P_L$ is the power of the lens and $P_M$ is the power of the mirror.For a

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(B) The power of the silvered lens system is given by $P = 2P_L + P_M$,where $P_L$ is the power of the lens and $P_M$ is the power of the mirror.For a plano-convex lens,the power $P_L = \frac{1}{f_L} = (\mu_g/\mu_l - 1)(1/R_1 - 1/R_2)$.Here,$\mu_g = 1.5$,$\mu_l = 1.2$,$R_1 = R$,and $R_2 = \infty$.So,$P_L = (1.5/1.2 - 1)(1/R - 0) = (1.25 - 1)/R = 0.25/R$.The mirror is the plane surface,so its power $P_M = -1/f_M$. Since it is a plane mirror,$f_M = \infty$,so $P_M = 0$.The effective focal length $F$ of the system is given by $1/F = -(2P_L + P_M)$.Given $F = -0.2 \ m$ (concave mirror),so $1/(-0.2) = -(2 	imes (0.25/R) + 0)$.$-5 = -0.5/R$.$R = 0.5/5 = 0.1 \ m$.

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