A compound X absorbs 2 moles of hydrogen and | vedclass

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(A) The oxidation products are $CH_3-CO-CH_3$,$CH_3-COOH$,and $CH_3-CO-CH_2-CH_2-COOH$. By analyzing the cleavage products,the structure of compound $

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$27$

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(A) The oxidation products are $CH_3-CO-CH_3$,$CH_3-COOH$,and $CH_3-CO-CH_2-CH_2-COOH$. By analyzing the cleavage products,the structure of compound $X$ is determined to be $CH_3-C(CH_3)=CH-CH_2-CH_2-CH=C(CH_3)_2$. This structure contains $2$ double bonds,which is consistent with the absorption of $2$ moles of hydrogen. To count the $\sigma$ bonds: - The carbon skeleton has $10$ carbon atoms,which implies $9$ $C$-$C$ $\sigma$ bonds. - The number of hydrogen atoms is $3+3+1+2+2+1+3+3 = 18$. - Thus,there are $18$ $C$-$H$ $\sigma$ bonds. - Total $\sigma$ bonds = $9$ ($C$-$C$) + $18$ ($C$-$H$) = $27$.

$A$ compound $X$ absorbs $2$ moles of hydrogen and $X$ upon oxidation with $KMnO_4 \mid H^{+}$ gives the products shown below:
$CH_3-CO-CH_3$,$CH_3-COOH$ and $CH_3-CO-CH_2-CH_2-COOH$.
The total number of $\sigma$ bonds present in the compound $X$ is . . . . . .

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$A$ compound $X$ absorbs $2$ moles of hydrogen and $X$ upon oxidation with $KMnO_4 \mid H^{+}$ gives the products shown below:$CH_3-CO-CH_3$,$CH_3-COOH$ and $CH_3-CO-CH_2-CH_2-COOH$.The total number of $\sigma$ bonds present in the compound $X$ is . . . . . .