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Question

(A) The formula for Young's modulus $(Y)$ is given by $Y = \frac{F \cdot L}{A \cdot \Delta L}$.Here,$F = mg = 50 	imes 3 \pi \ N$,$L = 3 \ m$,$r = 3

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) The formula for Young's modulus $(Y)$ is given by $Y = \frac{F \cdot L}{A \cdot \Delta L}$.Here,$F = mg = 50 	imes 3 \pi \ N$,$L = 3 \ m$,$r = 3 	imes 10^{-3} \ m$,and $\Delta L = 0.1 	imes 10^{-3} \ m$.The area $A = \pi r^2 = \pi 	imes (3 	imes 10^{-3})^2 = 9 \pi 	imes 10^{-6} \ m^2$.Substituting these values into the formula:$Y = \frac{(50 	imes 3 \pi) 	imes 3}{(9 \pi 	imes 10^{-6}) 	imes (0.1 	imes 10^{-3})}$$Y = \frac{450 \pi}{0.9 \pi 	imes 10^{-9}} = \frac{450}{0.9} 	imes 10^9 = 500 	imes 10^9 = 5 	imes 10^{11} \ Nm^{-2}$.Comparing this with $P 	imes 10^{11} \ Nm^{-2}$,we get $P = 5$.

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