1, 2-dibromocyclooctane xrightarrow[substack{ | vedclass

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Question

(B) The reaction sequence is as follows:$1$. Dehydrohalogenation of $1, 2-$dibromocyclooctane with alc. $KOH$ followed by $NaNH_2$ yields cyclooctyne.

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Cyclooctane

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(B) The reaction sequence is as follows:$1$. Dehydrohalogenation of $1, 2-$dibromocyclooctane with alc. $KOH$ followed by $NaNH_2$ yields cyclooctyne.$2$. Hydration of cyclooctyne using $Hg^{2+} / H^{+}$ (Kucherov reaction) gives an enol intermediate,which tautomerizes to form cyclooctanone.$3$. Clemmensen reduction of cyclooctanone using $Zn-Hg / H^{+}$ reduces the carbonyl group to a methylene group,resulting in cyclooctane as the final major product $P$.

$1, 2-$dibromocyclooctane $\xrightarrow[\substack{\text{(ii) } NaNH_2 \\ \text{(iii) } Hg^{2+} / H^{+} \\ \text{(iv) } Zn-Hg / H^{+}}]{\text{(i) } KOH \text{ (alc.) }} \underset{\text{(Major product)}}{P}$. $P$ is

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