$A$ linear harmonic oscillator has a total mechanical energy of $300 \ J$. If its potential energy at the mean position is $100 \ J$,find its kinetic energy at $x = +\frac{A}{\sqrt{2}}$. (in $J$)

$A$ particle is executing simple harmonic motion with amplitude $A$. The ratio of the kinetic energies of the particle when it is at displacements of $\frac{A}{4}$ and $\frac{A}{2}$ from the mean position is

The variation of kinetic energy $(KE)$ of a particle executing simple harmonic motion with the displacement $(x)$ starting from mean position to extreme position $(A)$ is given by

At which point (place) does a particle executing $SHM$ have maximum kinetic energy and maximum potential energy?

$A$ mass $0.4 \text{ kg}$ performs $S.H.M.$ with a frequency $\frac{16}{\pi} \text{ Hz}$. At a certain displacement, it has kinetic energy $2 \text{ J}$ and potential energy $1.2 \text{ J}$. The amplitude of oscillation is (in $\text{ m}$)

$A$ particle starts oscillating simple harmonically from its equilibrium position with time period $T$. What is the ratio of potential energy to kinetic energy of the particle at time $t = \frac{T}{12}$? (Given: $\sin(\frac{\pi}{6}) = \frac{1}{2}$)