CH_3-CH=CH-CH=CH_2 xrightarrow[Zn]{O_3 / H_2O | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The ozonolysis of $CH_3-CH=CH-CH=CH_2$ involves the cleavage of both double bonds.Step $1$: The first double bond $(CH_3-CH=CH-)$ cleaves to form

Vedclass · Accepted Answer

$CH_3-CH_2-CHO$

Vedclass · Answer

(B) The ozonolysis of $CH_3-CH=CH-CH=CH_2$ involves the cleavage of both double bonds.Step $1$: The first double bond $(CH_3-CH=CH-)$ cleaves to form $CH_3-CHO$ and $OHC-$.Step $2$: The second double bond $(-CH=CH_2)$ cleaves to form $OHC-$ and $HCHO$.Step $3$: Combining the fragments,the products are $CH_3-CHO$,$OHC-CHO$ (glyoxal),and $HCHO$.Therefore,$CH_3-CH_2-CHO$ is not formed.

$CH_3-CH=CH-CH=CH_2 \xrightarrow[Zn]{O_3 / H_2O}$ Which will not form?

Similar Questions

Predict the major alkene product formed upon heating the following ester:

For the given reaction sequence,identify $C$ and $D$:
$3\text{-methylbut-1-ene}$ $\xrightarrow[(ii) NaBH_4]{(i) Hg(OAc)_2/H_2O} A$ $\xrightarrow{H^\oplus/\Delta} B$ $\xrightarrow{O_3/Zn/H_2O} C + D$

The product of acid catalyzed hydration of $2-$phenylpropene is

$1$-Methylcyclohexene reacts with $B_2H_6$. The product is then treated with $H_2O_2$ and $NaOH$. What will be the product of the reaction?

The major product in the reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module