A woman has a haemophilic son and three norma | vedclass

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(D) Haemophilia is an $X$-linked recessive disorder.Since the woman has a haemophilic son $(X^hY)$,the son must have inherited the $X^h$ chromosome fr

Vedclass · Accepted Answer

$X^hX$ and $XY$

Vedclass · Answer

(D) Haemophilia is an $X$-linked recessive disorder.Since the woman has a haemophilic son $(X^hY)$,the son must have inherited the $X^h$ chromosome from his mother.Therefore,the mother must be a carrier of the haemophilia gene,meaning her genotype is $X^hX$.Since the woman has three normal children,and the father is normal $(XY)$,the father's genotype is $XY$.If the father were haemophilic $(X^hY)$,he would pass the $X^h$ gene to all his daughters,making them carriers or affected,but the question implies the father is normal.

$A$ woman has a haemophilic son and three normal children. What is the genotype of the woman and her husband?

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