A ring of resistance 10 Omega,radius 10 cm | vedclass

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(B) Given: Resistance $R = 10 \ \Omega$,Radius $r = 10 \ cm = 0.1 \ m$,Number of turns $N = 100$,Frequency $f = 100 \ Hz$,Magnetic field $B = 10 \ mT

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(B) Given: Resistance $R = 10 \ \Omega$,Radius $r = 10 \ cm = 0.1 \ m$,Number of turns $N = 100$,Frequency $f = 100 \ Hz$,Magnetic field $B = 10 \ mT = 10^{-2} \ T$.Angular velocity $\omega = 2 \pi f = 2 \pi (100) = 200 \pi \ rad/s$.Area of the loop $A = \pi r^2 = \pi (0.1)^2 = 0.01 \pi \ m^2$.The peak electromotive force $(EMF)$ is given by $e_0 = N B A \omega$.Substituting the values: $e_0 = 100 	imes 10^{-2} 	imes 0.01 \pi 	imes 200 \pi = 1 	imes 0.01 	imes 200 	imes \pi^2$.Given $\pi^2 = 10$,so $e_0 = 0.01 	imes 200 	imes 10 = 20 \ V$.The amplitude of the current $I_0 = \frac{e_0}{R} = \frac{20 \ V}{10 \ \Omega} = 2 \ A$.

$A$ ring of resistance $10 \ \Omega$,radius $10 \ cm$ and $100$ turns is rotated at a rate of $100$ revolutions per second about its diameter perpendicular to a uniform magnetic field of induction $10 \ mT$. The amplitude of the current in the loop will be nearly $....... \ A$. (Take: $\pi^2 = 10$)

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